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7=3m^2+5m-2
We move all terms to the left:
7-(3m^2+5m-2)=0
We get rid of parentheses
-3m^2-5m+2+7=0
We add all the numbers together, and all the variables
-3m^2-5m+9=0
a = -3; b = -5; c = +9;
Δ = b2-4ac
Δ = -52-4·(-3)·9
Δ = 133
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{133}}{2*-3}=\frac{5-\sqrt{133}}{-6} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{133}}{2*-3}=\frac{5+\sqrt{133}}{-6} $
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